D1 = persegi panjang
L = 512 m²
p = 2l
D3 = L = p.l
512 m² = 2l.l
512/2 = l²
256 = l²
16 = l
p = 3l
p = 3(16)
p = 48
panjang diagonal
= 16² + 48²
= 256 + 2.304
= 2560
= √256
= 16√10 cm
Penjelasan dengan langkah-langkah:
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
[tex] \tt = {16}^{2} + {48}^{2} [/tex]
[tex] \tt = 256 + 2.304[/tex]
[tex] \tt = 2560[/tex]
[tex] \tt = \sqrt{256} [/tex]
[tex] \tt = 16 \sqrt{10} \: cm[/tex]
Thx!
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D1 = persegi panjang
L = 512 m²
p = 2l
D3 = L = p.l
512 m² = 2l.l
512/2 = l²
256 = l²
16 = l
p = 3l
p = 3(16)
p = 48
panjang diagonal
= 16² + 48²
= 256 + 2.304
= 2560
= √256
= 16√10 cm
Penjelasan dengan langkah-langkah:
--
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
Panjang Diagonal :
[tex] \tt = {16}^{2} + {48}^{2} [/tex]
[tex] \tt = 256 + 2.304[/tex]
[tex] \tt = 2560[/tex]
[tex] \tt = \sqrt{256} [/tex]
[tex] \tt = 16 \sqrt{10} \: cm[/tex]
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
--
Thx!