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B. 3, 4 dan 5....... 3^2 + 4^2 = 5^2= 9 + 16 = 25
Rumus untuk menentukan jenis segitiga :
⇒ Jika a² - b² + c² → Δ. siku siku
⇒ Jika a² < b² + c² → Δ. lancip
⇒ Jika a² > b² + c² → Δ. tumpul
Maka :
1) 2 cm, 3 cm, 4 cm
4² = 3² + 2²
16 = 9 + 4
16 = 13
16 > 13 → Δ. tumpul
2) 3 cm, 4 cm, 5 cm
5² = 4² + 3²
25 = 16 + 9
25 = 25 → Δ. siku siku
3) 4 cm, 5 cm, 6 cm
6² = 5² + 4²
36 = 25 + 16
36 = 41
36 < 41 → Δ. lancip
4) 6 cm, 7 cm, 8 cm
8² = 7² + 6²
64 = 49 + 36
64 = 85
64 < 85 → Δ. lancip
Maka ukuran sisi yang dapat membentuk Δ. siku² = 3 cm, 4 cm, 5 cm