Question

Panjang suatu persegi panjang (3x+2)cm dan lebar (2x-1)cm.jika kelilingnya 60cm.hitunglah luasnya

Answer 1

2p+2l=60

[2(3x+2)] + [2(2x-1)] = 60
6x+4+4x-2=60
10x = 60-4+2
10x = 58
x=5,8

Luas = p.l
= (3(5,8)+2)) . (2(5.8-1))
=........
good luck

Answer 2

K = 2( p+l)
60 = 2 ( 3x + 2 + 2x - 1 )
60 = 2 ( 5x +1)
60 = 10x + 2
60 - 2 = 10 x
58 = 10x
x= 58 ÷ 10
= 5,8
jadi
L = p .l
= ( 3x +2 ) ( 2 x - 1)
= ( 3(5,8) + 2) ( 2 (5,8) -1)
( 17,8 + 2 ) (11,6 - 1)
= (19,4) (10,6)
= 205,64 cm
jadi luasnya 205,65 cm