Panjang suatu persegi panjang (2x+3) cm dan lebarnya (x-2) cm. jika keliling persegi panjang itu 74 cm, maka buatlah persamaan dalam x dan tentukan panjang dan lebar persegi panjang tersebut.
K = 2 (P+L) 74 = 2 ((2x+3)+(x-2)) 74 = 4x+2x+6-4 74 = 6x + 2 6x = 74-2 6x = 72 x = 72/6 x = 12 cm
P = 2x+3 P = 2(12)+3 P = 24+3 P = 27 cm
L = x-2 L = 12-2 L = 10 cm
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naruesty
Dik : panjang= 2x + 3 cm lebar= x - 2 cm keliling= 74 cm dit= panjang= ... ? penyelesaian=
keliling= 2( p + l ) 74cm = 2 ( (2x + 3) + (x - 2) )cm 74 cm = 2 ( 3x + 1 ) cm 74 cm = (6x + 2 ) cm 74 - 2 cm = 6x cm 72 cm = 6x cm 72 x = ----- 6 x= 12
substitusi nilai x = 12 ke p= 2x + 3 cm = 2(12) + 3 = 24 + 3 = 27
P = (2x+3)cm
L = (x-2)cm
K = 2 (P+L)
74 = 2 ((2x+3)+(x-2))
74 = 4x+2x+6-4
74 = 6x + 2
6x = 74-2
6x = 72
x = 72/6
x = 12 cm
P = 2x+3
P = 2(12)+3
P = 24+3
P = 27 cm
L = x-2
L = 12-2
L = 10 cm
panjang= 2x + 3 cm
lebar= x - 2 cm
keliling= 74 cm
dit= panjang= ... ?
penyelesaian=
keliling= 2( p + l )
74cm = 2 ( (2x + 3) + (x - 2) )cm
74 cm = 2 ( 3x + 1 ) cm
74 cm = (6x + 2 ) cm
74 - 2 cm = 6x cm
72 cm = 6x cm
72
x = -----
6
x= 12
substitusi nilai x = 12 ke
p= 2x + 3 cm
= 2(12) + 3
= 24 + 3
= 27
l = x-2 cm
= 12-2
= 10 cm
luas= p.l
= 27 . 10 cm²
= 270 cm²