Panjang lebar dan tinggi sebuah balok berbanding sebagai berikut 5:3:2.jika volume balok itu 1.920cm³,maka luas alasnya adalah.......
KDSlasher
Misal panjang, lebar, dan tinggi balok adalah 5a, 3a, dan 2a, maka V = 5a x 3a x 2a 1920 = 30a^3 a^3 = 1920 / 30 = 64 a = 4 p = 5a = 5 x 4 = 20 l = 3a = 3 x 4 = 12 L alas = 20 x 12 = 240 cm2
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Aliffajar
P:l:t=5:3:2 p=5x l=3x t=2x v=1920 v=p*l*t p*l*t = 1920 5x*3x *2x =1920 30 x pangkat 3 = 1920 x pangkat 3 = 1920 / 30 x pangkat 3 = 64 x = ∛64 x = 4 p = 5x = 5*4 =20 cm l = 3x = 3*4 = 12 cm Luas alas = p*l =20*12 = 240 cm²
V = 5a x 3a x 2a
1920 = 30a^3
a^3 = 1920 / 30
= 64
a = 4
p = 5a = 5 x 4 = 20
l = 3a = 3 x 4 = 12
L alas = 20 x 12 = 240 cm2
p=5x
l=3x
t=2x
v=1920
v=p*l*t
p*l*t = 1920
5x*3x *2x =1920
30 x pangkat 3 = 1920
x pangkat 3 = 1920 / 30
x pangkat 3 = 64
x = ∛64
x = 4
p = 5x
= 5*4
=20 cm
l = 3x
= 3*4
= 12 cm
Luas alas = p*l
=20*12
= 240 cm²