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jarak pusat = 34 cm
R = 9 cm
r = 7 cm
≡ ditanya : Garis singgung persekutuan dalam ( gspd ) ?
≡ penyelesaian :
gspd = √ jarak pusat² - ( R + r )²
gspd = √ 34² - ( 9 + 7 )²
gspd = √ 1156 - 16²
gspd = √ 1156 - 256
gspd = √ 900
gspd = 30 cm [ jawaban ]
jari jari 1=9cm
jari jari 2=7cm
Dit:PGSD=?
Jwb:PGSD=jp^2-(R+r)^2
=34^2-(9+7)^2
=1156-256
=900cm