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Prhtikan 3 buah sgitga siku2 brikut :
sgi3 AFC, maka berlaku :
AC^2 = AF^2 + CF^2 (pythagoras)
AC^2 = 11^2 + 12^2
sgi3 AEC, maka berlaku :
EC^2 = AC^2 - EA^2 (pythagoras)
EC^2 = 11^2 + 12^2 - x^2
sgi3 CDE, maka berlaku :
EC^2 = CD^2 - DE^2 (pythagoras)
11^2 + 12^2 - x^2 = 20^2 - (15 - x)^2 (prhtikan CD=AB=11+9=20)
121 + 144 - x^2 = 400 - (225 - 30x + x^2)
265 - x^2 = 400 - 225 + 30x - x^2
265 = 175 + 30x
30x = 265 - 175
30x = 90
x = 90/30 = 3
so, EA = x = 3 cm
20x12 = 15xCE
CE = 16
segitiga CDE
EA = DA - DE = 15 - 12 = 3