Panjang diagonal diagonal suatu belah ketupat adalah 15cm dan (3X+2)cm. jika luas belah ketupat itu 150cm persegi.tentukanlah a.nilai X b.panjang diagonal kedua
Beta27
L = d1 x d2 x 1/2 150 = 15 (3x + 2) x 1/2 150 x 2 = 15(3x + 2) 300 = 45x + 30 300-30 = 45x 270 = 45x 270/45 = x 6 = x
maka nilai x = 6
maka diagonal kedua d2 = 3x + 2 = 3(6) + 2 = 18 + 2 = 20 cm
mk : L = D1xD2 / 2 150 = [15 x (3x+2)]/2 150 x 2 = 15x + 30 300 = 15x + 30 15x = 300-30 x = 270/15 x = 18 cm a. jd x = 18 cm b. pnjng digonal 2 = 3x+2 = 3(18) + 2= 56 cm
150 = 15 (3x + 2) x 1/2
150 x 2 = 15(3x + 2)
300 = 45x + 30
300-30 = 45x
270 = 45x
270/45 = x
6 = x
maka nilai x = 6
maka diagonal kedua
d2 = 3x + 2 = 3(6) + 2 = 18 + 2 = 20 cm
D1 = 15 CM
D2 = (3x+2)
L = 150
mk :
L = D1xD2 / 2
150 = [15 x (3x+2)]/2
150 x 2 = 15x + 30
300 = 15x + 30
15x = 300-30
x = 270/15
x = 18 cm
a. jd x = 18 cm
b. pnjng digonal 2 = 3x+2 = 3(18) + 2= 56 cm