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DE = √(12² + 9²)
DE = √(144 + 81)
DE = √225
DE = 15 cm
Panjang AE = √(BE² + AB²)
AE = √(6² + (4,5)²)
AE = √(36 + 20, 25)
AE = √56, 25
AE = 7, 5 cm
Panjang AD = 15 + 7, 5 = 22, 5 cm
Maka berlaku,
AB/BE = CD/CE
AB = (BE x CD)/CE
AB = (6 x 12) / 9
Diperoleh AB = 8 cm.
Secara phytagoras pada segitiga ABE, didapat AE = 10 cm.
Begitu juga secara phytagoras pada segitiga CDE, didapat DE = 15 cm.
Sehingga panjang AD = AE + ED = 10 + 15 = 25 cm.