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Verified answer
KELAS = 12PELAJARAN = FISIKA
KATEGORI = Gelombang cahaya
KATA KUNCI = Difraksi celah tunggal, orde dua, panjang gelombang
Diketahui :
θ = 30
d = 3x10⁻⁴ cm = 3x10⁻⁶ m
orde ke dua = n = 2
1Â = 1x10⁻¹⁰ m
Ditanyakan : Panjang gelombang ?
Dijawab :
Panjang gelombang :
λ x n = d sin θ
λ x 2 = 3x10⁻⁶ x sin 30
λ = 3x10⁻⁶ x 0,5 / 2
= 0,75x10⁻⁶ m
= 7500 x 10⁻¹⁰ m
= 7500 Â
jawaban D