8] Luas permukaan = 576 cm² (2 x Luas alas) + Luas sisi tegak = 576 2 x Luas alas + 332 = 576 2 x Luas alas = 576 - 332 2 x Luas alas = 244 Luas alas = 244 / 2 Luas alas = 122 cm²
9] a = 8 cm b = 12 cm t = 5 cm T = 10 cm
Volume = 1/2 x (a + b) x t x T = 1/2 x (8 + 12) x 5 x 10 = 1/2 x 20 x 5 x 10 = 500 cm³
10] Volume = 1/3 x Luas alas x t 567 = 1/3 x La x 21 567 = 7 x La La = 567 / 7 La = 81 cm²
La = 81 cm² s² = 81 cm² s = √81 cm² s = 9 cm
diagonal bidang alas = s√2 = 9√2 cm
11] a = 3 cm t = 4 cm T = 20 cm
Volume = Luas alas x tinggi = 1/2 x a x t x T = 1/2 x 3 x 4 x 20 = 120 cm³
Verified answer
8]Luas permukaan = 576 cm²
(2 x Luas alas) + Luas sisi tegak = 576
2 x Luas alas + 332 = 576
2 x Luas alas = 576 - 332
2 x Luas alas = 244
Luas alas = 244 / 2
Luas alas = 122 cm²
9]
a = 8 cm
b = 12 cm
t = 5 cm
T = 10 cm
Volume
= 1/2 x (a + b) x t x T
= 1/2 x (8 + 12) x 5 x 10
= 1/2 x 20 x 5 x 10
= 500 cm³
10]
Volume = 1/3 x Luas alas x t
567 = 1/3 x La x 21
567 = 7 x La
La = 567 / 7
La = 81 cm²
La = 81 cm²
s² = 81 cm²
s = √81 cm²
s = 9 cm
diagonal bidang alas
= s√2
= 9√2 cm
11]
a = 3 cm
t = 4 cm
T = 20 cm
Volume
= Luas alas x tinggi
= 1/2 x a x t x T
= 1/2 x 3 x 4 x 20
= 120 cm³
(576 - 332) / 2 = 244 / 2
= 122cm^2
no. 9
V. prisma = ((8 + 12) × 5 / 2) × 10
= 50 × 10
= 500cm^3
no. 10
567 = 1/3 × s^2 × 21
567 = 7 × s^2
s^2 = 81
s = 9cm
p. diagonal bidang = akar (9^2 + 9^2)
= akar (81 + 81)
= akar 162
= 9 akar 2
no. 11
V. prisma = 3 × 4 / 2 × 20
= 120cm^3