Jawaban:
no 6
AC = √10²+24²
=√200+576
= √676 = 26
kll =AC +AB +BC
= 26+10+24
=60 CM
JADI JWABN NYA D
6. Cari AC dengan pythagoras.
AC = √(AB² + BC²) = √(10² + 24²) = √(100 + 576) = √676 = 26 cm
Keliling ΔABC = AB + BC + AC
= 10 + 24 + 26
= 60 cm [D.]
7. AB² = BC² - AC²
(2x + 1)(2x + 1) = 5² - 4²
4x² + 4x + 1 = 25 - 16
4x² + 4x + 1 = 9
4x² + 4x + 1 - 9 = 0
4x² + 4x - 8 = 0 → kedua ruas dibagi 4
x² + x - 2 = 0
(x - 1)(x + 2) = 0
x - 1 = 0 atau x + 2 = 0
x = 1 atau x = -2
Jadi, nilai x adalah 1 [A.].
8. a² = 10,4² - 9,6²
a = √(10,4² - 9,6²) = √(108,16 - 92,16) = √16 = 4 cm [D.]
[tex]\boxed{\sf{shf}}[/tex]
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Verified answer
Jawaban:
no 6
AC = √10²+24²
=√200+576
= √676 = 26
kll =AC +AB +BC
= 26+10+24
=60 CM
JADI JWABN NYA D
Pythagoras
6. Cari AC dengan pythagoras.
AC = √(AB² + BC²) = √(10² + 24²) = √(100 + 576) = √676 = 26 cm
Keliling ΔABC = AB + BC + AC
= 10 + 24 + 26
= 60 cm [D.]
7. AB² = BC² - AC²
(2x + 1)(2x + 1) = 5² - 4²
4x² + 4x + 1 = 25 - 16
4x² + 4x + 1 = 9
4x² + 4x + 1 - 9 = 0
4x² + 4x - 8 = 0 → kedua ruas dibagi 4
x² + x - 2 = 0
(x - 1)(x + 2) = 0
x - 1 = 0 atau x + 2 = 0
x = 1 atau x = -2
Jadi, nilai x adalah 1 [A.].
8. a² = 10,4² - 9,6²
a = √(10,4² - 9,6²) = √(108,16 - 92,16) = √16 = 4 cm [D.]
[tex]\boxed{\sf{shf}}[/tex]