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r1 = 21 cm
t1 = 5 cm
π = 22/7
luas lingkaran luar :
L1 = π × r²
L1 = 22/7 × 21²
L1 = 1386 cm²
luas selimut :
L2 = 2 × π × r × t
L2 = 2 × 22/7 × 21 × 5
L2 = 660 cm²
luas lingkaran dalam
L3 = π × r1² - π × r2²
L3 = 22/7 × 21² - 22/7 × 7²
L3 = 1386 - 154
L3 = 1232 cm²
luas permukaan 2 tabung besar :
LB = 2 × ( L1 + L2 + L3 )
LB = 2 × ( 1386 + 660 + 1232 )
LB = 2 × 3278 cm²
LB = 6556 cm²
luas permukaan tabung kecil
r2 = 7 cm
t2 = 50 cm
LK = 2 × π × r2 × t
LK = 2 × 22/7 × 7 × 50
LK = 2200 cm²
luas permukaan bangun
L = LB + LK
L = 6556 + 2200
L = 8756 cm²