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Verified answer
U2+U4= a+b+a+3b= 12U3+U5= a+2b+a+4b= 16
2a+4b=12
2a+6b= 16
Eliminasi
(2a+6b)-(2a+4b)= 16-12
2b= 4
b= 2
Substitusi ke salah satu persamaan
2a+4b=12
2a+ 4.2= 12
2a= 12-8= 4
a= 2
U7= a+6b= 2+6.2= 14