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BC = alas
AC = tinggi
LΔ ABC = 1/2.a.t
sin 75° =
cos 75° =
maka luas Δ ABC = [tex] \frac{1}{2} . \frac{10}{4} ( \sqrt{6} + \sqrt{2} ). \frac{10}{4} ( \sqrt{6} - \sqrt{2} ) \\ = \frac{25}{8}.(( \sqrt{6} ) ^{2} -( \sqrt{2} ) ^{2} ) \\ = \frac{25}{8} .4 \\ = \frac{25}{2} cm persegi