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Reaksi setaranyaH2SO4 + 8HI ---> H2S + 4I2 + 4H2O
maka 2 mol H2SO4 = 8x2= 16 mol HI
(SO4)²- + 8e + 8H+ ==> S²- + 4H2O x1
2 I- ==> I2 + 2e x4
(SO4)²- + 8H+ + 8 I- ==> S²- + 4H2O
H2SO4 + 8HI ===> H2S + 4H2O
mol H2SO4 = 2 mol
mol HI = 8/1 x 2 = 16 mol