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Luas: l x p
Panjang: 2x + 4
Lebar: 4 + x
Pengerjaan:
a. 2 (2x + 4 + 4 + x)
=> 2 (3x + 8)
=> 6x + 8
Jadi, kelilingnya 6x + 8
b. (2x + 4) (4 + x)
= 8x + 2x² + 16 + 4x
= 8x + 4x + 2x² + 16
= 12x + 2x² + 16
Jadi, luas persegi panjangnya 12x + 2x² + 16
tanya: a. k? , b. L?
jawab:
k = 2(p+l)
k= 2(2x+4+4+x)
k= 2(2x+x+4+4)
k= 2(3x+4)
k= 6x+8
L = p x l
L= (2x+4) x (4 + x)
L= 8x+2x²+16+4x
L= 8x+4x+2x²+16
L= 12x +2x²+16
(maaf kalau salah....)