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Verified answer
Diketahui:l = 1 m = 10^3 mm
d = 2 mm
lamda = 600 nm = 6x10^-4 mm
ditanya y = ?
jawab:
a) dy/l = n.(lamda) ==> n = 3 (terang pusat ke terang ketiga)
2 (y)/10^3 = 3 (6x10^-4)
y = 9 x 10^-1 mm
b) dy/l = n.(lamda) ===> n = 3/2 (terang pusat ke gelap kedua)
2 (y)/10^3 = 3/2(6x10-4)
y = 4,5 x 10^-1 mm
maaf kalo salah
• interferensi
L = 1 m
d = 2 mm = 2×10^-3 m
λ = 600 nm = 6×10^-7 m
y = __?
a][ terang ketiga → m = 3
y d / L = m λ
y = m λ L / d
y = 3 • 6×10^-7 • 1 / 2×10^-3
y = 9×10^-4 m = 0,9 mm ← jwb
b][ gelap kedua → m = 1½
y d / L = m λ
y = m λ L / d
y = (3/2) • 6×10^-7 • 1 / 2×10^-3
y = 4,5×10^-4 m = 0,45 mm ← jwb