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soal ujian tahun 2002
Dengan OB adalah setengah diagonal sisi, maka:
OB = ½ a√2
Maka,
tan a = FB/OB
tan a = a / (½a√2)
tan a = a/(1/√2)
tan a = √2
Dengan,
y = √2
x = 1
r = √5
Maka,
sin a = y/r
sin a = √2/√5
sin a = 1/5 √10