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jika p dan q adalah akar2 persamaan dari x² + 3x -2 =0
maka p + q = -b/a = -3/1 = -3
dan pq = c/a = -2/1 = -2
(p + q)²= p² + q² + 2pq
(-3)² = p² + q² + 2(-2)
9 = p² + q² -4
p² + q² = 13
jadi nilai p/q + q/p = (p² + q²)/ pq = 13/-2 = - 6,5