mCa=40umBr=2*80=160ustosunek 40:160 1:4mFe=56*2=112umO=16*3=48ustosunek 112:48 7:3
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mCa=40u
mBr=2*80=160u
stosunek 40:160 1:4
mFe=56*2=112u
mO=16*3=48u
stosunek 112:48 7:3