Określ dziedzinę i wykonaj działania:
a)
4x²-6x+9 8x³+27
----------------- : ---------------- =
4x²-9 (2x+3)³
9x²+6x+4 8-27x³
b) --------------- : --------------- =
4-9x² (3x-2)³
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
zad.a/ 4x²-9≠0 i (2x+3)³≠0
4x²≠9 2x+3≠∛0≠0
x²≠9/4 2x≠-3
x≠±√9/4 x≠-3/2
x≠±3/2
Df∈R\{-3/2, 3/2}
4x²-6x+9 8x³+27 2x(2x-3)+9 8x³+27 2x(2x-3)+9
--------------- : -------------- = ------------------- : ------------------- = ----------------- ·
4x²-9 (2x+3)³ (2x+3)(2x-3) (2x+3)(2x+3)² (2x-3)(2x+3)
(2x+3)(2x+3)² (4x²-6x+9)(2x+3)² (4x²-6x+9)(4x²+12x+9)
------------------- = -------------------------- = --------------------------------- =
8x³+27 (2x-3)(8x³+27) 16x⁴+54x-24x³-81
16x⁴+48x³+36x²-24x³-72x²-54x+36x²+108x+81 16x⁴+24x³+54x+81
------------------------------------------------------------- = ----------------------------- cdn
16x⁴-24x³+54x-81 16x⁴-24x³+54x-81