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d. D=R
a. D=R
b. x₁+2=0
x₁=-2
x²+2x+1=0
Δ=4-4•1=0
x₂=-2\2
x₂= -1
D=R\{-2,-1}
:)
x≥5 x≤5
odp. x=5
d) /x/ - x ≠ 0
dla x≥0 ∨ dla x < 0
x-x≠0 -x-x≠0
0≠0 -2x≠0/(-2)
sprzeczność x≠0
x nalezy do zbioru pustego
odp.x∈R/{0}
a)x+1≥0 ∧ x≠0
x≥-1
odp.x∈ <-1, 0) i (0, ∞)
b) x+2≠0 ∧ x² + 2x +1 ≠ 0
x≠-2 (x+1)² ≠0
x+1≠0
x≠-1
odp. x∈ R/{-2,-1}