Odbiornik 20ohma zużywa kilowatogodzinę w ciągu 30 min. Jakie jest natężenie prądu wpływającego do odbiornika?
R = 20 Ω
W = 1 kWh =1000W * 3600 s = 3600 000 J
t = 30 min = 1800 s
W = U*I*t
I = U/R
U = I*R
W = I*R*I*t
W = I²*R*t /: R*t
W/R*t = I²
I = √(W/Rt)
I = √(3600 000/20*1800) = √100 = 10 A
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R = 20 Ω
W = 1 kWh =1000W * 3600 s = 3600 000 J
t = 30 min = 1800 s
W = U*I*t
I = U/R
U = I*R
W = I*R*I*t
W = I²*R*t /: R*t
W/R*t = I²
I = √(W/Rt)
I = √(3600 000/20*1800) = √100 = 10 A