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α = 10^-5
T1 = 30³C
ΔL = 100,1 - 100 = 0,1 cm = 10^-3 m
Ditanya :
T2
Jawab
ΔL = Lo . α . ΔT
10^-3 = 1 . 10^-5 . ΔT
ΔT = 10^-3 / 10^-5
ΔT = 10²
ΔT = 100
ΔT = T2 - T1
100 = T2 - 30
T2 = 100 + 30
T2 = 130³C
Δl = 100,1 - 100
= 0,1 Cm = 10^-3 m
Δl = lo x α x Δt
10^-3 = 1 x 10^-5 x (tx - 30)
tx - 30 = 10^-3 / 10^-5
tx - 30 = 100
tx = 130 derajat C