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b=a +2 -ramie
Ob=a +2b=a+ 2(a+2)= a+ 2a +4=3a +4
ob=34
3a+4=34
3a=30
a=10
b=a+2=10+2=12
teraz z tw pit
(1/2a)²+h²=b²
25+h²=144
h²=119
h=√119
Pole
P=1/2a h
P=1/2 *10 *√119=5√119cm²
c - ramię
a + 2c = 34
c = a + 2
a + 2a + 4 = 34
3a = 30
a = 10
c = 12
h = ?
tw. pitagorasa
(a/2)² + h² = c²
h² = c² - (a/2)² = 144 - 25 = 119
h = √119
P = ah/2 = 10√119/2 = 5√119
y-dlugosc jednego ramienia
ob=34cm
y=x+2
x+2y=34
y=x+2
x+2*(x+2)=34
y=x+2
x+2x+4=34
y=x+2
3x=34-4
y=x+2
3x=30
y=x+2
x=10
y=10+2
x=10
y=12
x=10
1/2 x=5
h²+5²=12²
h²+25=144
h²=144-25
h²=119
h=√119
P=1/2a * h
P=5√119