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80 = 2a + 2b
a - 5 = b + 5
a = b + 10
80 = 2 * (b + 10) + 2b
80 = 2b + 20 + 2b
60 = 4b /: 4
b = 15
a = 10 + 15
a = 25
2 * 25 + 2 * 15 = 50 + 30 = 80
25 - 5 = 15 + 5
20 = 20
Więc bok a ma 25 cm, a bok b 15 cm.
Pole: 25 * 15 = 375 cm^2
Przekątna z Pitagorasa:
25^2 + 15^2 = d^2
625 + 225 = d^2
d^2 = 850
d = p850
d = 5p34
b - krótszy bok
2a+2b=80
80 = 2a + 2b
a - 5 = b + 5
80 = 2a + 2b
a = b + 10
80 = 2 * (b + 10) + 2b
80 = 2b + 20 + 2b
60 = 4b /: 4
b = 15
a = 10 + 15
a = 25
2 * 25 + 2 * 15 = 50 + 30 = 80
25 - 5 = 15 + 5
20 = 20
Odp. Bok a ma 25 cm, a bok b 15 cm.
Pole: 25 * 15 = 375 cm^2
Pitagorasem:
25^2 + 15^2 = d^2
625 + 225 = d^2
d^2 = 850
d = pierwiastek z 850
d = 5 pierwiastków z 34
Odp. Przekątna wynosi 5 pierwiastków z 34
x+5 - dluzszy bok prostokata
x-5 - krotszy bok
O=80cm
2*(x+5)+ 2*(x-5)=80cm
2x+10 + 2x-10=80cm
80cm= 4x
x= 20cm
x+5=20+5=25cm - dluzszy bok
x-5=20-5=15cm -krotszy bok
P= 25 * 15 = 375 cm²
d- przekatna
a²+b²=d²
15²+25²=d²
225+625= d²
d=√850
d= 5√34