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2a + 2b = 30
ab = 44
a+b = 15
ab = 44
a = 15-b
b(15-b) = 44
-b² + 15b - 44 = 0
Δ = 15²-4*(-1)*(-44) = 49
b₁ = (-15 - 7)/-2 = 11
b₂ = (-15+7)/-2 = 4
a₁ = 15-11 = 4
a₂ = 15 - 4 = 11
Odp: to jest prostokąt o wymiarach: 4cmx11cm
a+b=15
a*b=44
a=44/b
44/b+b=15
44+b^2=15b
b^2-15b+44=0
delta=225-176=49
pierw z delty=7
b=[15(+/-)7]/2=11 lub 4
Odp Boki mją długości 11 i 4