obwod prostokata wynosi 36 cm.roznica dwoch bokow wychodzacych z jednego wierzcholkawynosi 10.oblicz dlugosci bokow i pole powierzchni tego prostokata.
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x - jeden bok
x+10 drugi bok
2*(x+x+10)=36
2x+10=18
2x=8
x=4
4cm = pierwszy bok
4+10=14cm = drugi bok
P=4cm*14cm=56cm²