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V=Pp*H= πr²*H= 40π
Pc= 2πr(r+H)= 2π*2*12= 48π
b)2r= 6 więc r= 3 i H=8
V= π*3²*8= 72π
Pc= 2π*3*11= 66π
c) r= 4 (z twierdzenia Pitagorasa wysokość²+średnica²= przekątna walca² :)
H= 6
V= π*4²*6= 64π
Pc= 2π*4*10= 80π