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Wzór na obj : v=⅓Pph
Pp=πr² Pp=π5² Pp=25π
v=⅓×25π×20
v=7,5x25π
v=7,5x25x3,14
v=7,5x78,5
v=588,75cm³
Pole stożka
Pc=Pb+Pp
Pp=25π
Pb=πrl
l=√h²+r²
l=√400+25
l=5√17
Pb=πx5x5√17
Pb=5πx5√17
Pc=5π+25πx5√17
Pc=25πx5√17
Objętość walaca
V=πr²H
V=πx25x20
v=500π
v=500x314
v=1570cm³
Pole walca
Pp=πr²=25π=78,5
Pb=2πrH=2πx5x20=2πx100=200π=200x3,14=628
Pc=2x78,5+628=157+628=785cm ;D
20²+5²=l²
400+25=l²
l²=425
l= √400+√25
l=20+5
l=25
P=πrl+πr²
P= π5*25+π5²
P=π125+π25
P=150π
V=πr²*H/3
V=π5²*20/3
V=π25*20/3
V=500π/3
Walec
V=πr²*H
V=π5²*20
V=π25*20
V=500π
Pc=2πr²+2πrH
Pc=2π5²+2π5*20
Pc=2π25+2π100
Pc=50π+200π
Pc=250π