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0,5mola ------- 1dm3
x mola --------- 0,125dm3
x = 0,0625mola NaOH
0,0625mola - 0,04mola = 0,0225mola
0,0225mola ------- 0,125dm3
x mola ----------------- 1dm3
x = 0,18mola/dm3
zasady jest w nadmiarze, liczymy pOH
pOH = -log(OH⁻)
pOH = -log(0,18)
pOH = 0,74