October 2018 1 9 Report

Oblicz.

\sqrt[3]{\frac{1}{64}} + \sqrt{16} (razy) \frac{3}{4^{2}} = \sqrt{16} : \sqrt{4} : (-2) ^{3} (razy) (-\frac{1}{4})^{1} = \sqrt[3]{8^{2}-3^{2} + (-3)^{2}} = \sqrt{(-4)^{2} -\sqrt{49}} =

Proszę o odpowiedzi!!!

Potrzebuję na dzisiaj!!!

Tak gdzie jest równa się(=) to koniec działania ;)


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