HCOOH + 1/2 O2 -> CO2 + H2O
6,9g xg
46g 16g
x= 6,9*16/46=2,4g
6,9g x
2HCOOH + O₂ ---> 2CO₂ + 2H₂O
92g 32g
x=32g·6,9g/92g=2,4g
Odp.: Potrzeba 2,4g tlenu.
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HCOOH + 1/2 O2 -> CO2 + H2O
6,9g xg
46g 16g
x= 6,9*16/46=2,4g
6,9g x
2HCOOH + O₂ ---> 2CO₂ + 2H₂O
92g 32g
x=32g·6,9g/92g=2,4g
Odp.: Potrzeba 2,4g tlenu.