Oblicz:
(cos150 + sin135)(cos30 + sin45)
Proszę o obliczenia, a nie same odpowiedzi
0blicz ; (sin60-2cos135/tg120)^2=-(0.304-0,99/0,71)^2=
= (2-cos135/tg120)^2=(2-cos135)^2/tg120^2=8,976/0,508=17,65
( cos150 + sin135)(cos30 + sin45)=(0,699+0,088)*(0,154+0,850)=
=0,787*1,005=0,791
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0blicz ; (sin60-2cos135/tg120)^2=-(0.304-0,99/0,71)^2=
= (2-cos135/tg120)^2=(2-cos135)^2/tg120^2=8,976/0,508=17,65
( cos150 + sin135)(cos30 + sin45)=(0,699+0,088)*(0,154+0,850)=
=0,787*1,005=0,791