Question

Oblicz:

b. x(2x-1)=2(x+2)^2

c. (x-5)^2=(x-pierwiastek z 3)(x+pierwiastek z 3)

d.(3-2x)^2+(x+4)(x-3)=5(x-2)^2+7

Proszę o pomoc!!! ;-))

Help Me!

Answer 1

b)x(2x-1)=2(x+2)^2

2x^2-x=2(x^2+4x+4)

2x^2-x=2x^2+4x+8

-5x=8

x=-0,625

 

(x-5)^2=(x-pierwiastek z 3)(x+pierwiastek z 3)

x^2-10x+25=x^2-3

-10x=-28

x=2,8

 

(3-2x)^2+(x+4)(x-3)=5(x-2)^2+7

9-12x+4x^2+x^2-3x+4x-12=5(x^2-4x+4)+7

-3-11x+5x^2=5x^2-20x+20+7

-30-11x=-20x

-20x=-41x

x=2,05

 

Answer 2

b) x(2x-1)=2(x+2)^2

2x^2-x=2(x^2+4)

2x^2-x=2x^2+8

2x^2-x-2x^2=8

-x=8 /*-1

x=-8

c)(x-5)^2=(x-√3)(x+√3)

x^2+25=x^2-3

x^2-x^2=-3-25

0=-28

d) (3-2x)^2+(x+4)(x-3)=5(x-2)^2+7

9+4x^2+x^2-12=5(x^2-4)+7

9+4x^2+x^2-12=5x^2-20+7

4x^2+x^2-5x^2=-20+7-9+12

0=-10