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D: 1-x²>0⇔(1-x)(1+x)>0⇔x∈(-1,1)
1-x²=(1/9)(^(3/2)
1-x²=1/27
26/27=x²⇔x=√(26/27) ∨ x=-√(26/27) obydwie liczby należą do D
1.
2^(2x)*3^(x-2)=2^x
2^x*3^x=9
6^x=9
teraz powinno być okey:)