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v=6,28*6400km/24h
v=1674,7km/h
r=6 400 000m
T=24h=86 400s
π≈3,14
Wzór:
V=2πr/T
rozwiązanie:
V=12800000m*3,14/86400s
V≈465,9m/s
Odp. Szybkość obrotu Ziemi wynosi 465,9m/s
ω=2π/T
V=ω*r
V=2π*r/T=2π*6400km/24h=533,34*π km/h≈1675 km/h