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m(C₁₅H₃₁COO)₂Ca=32*12u+62*1u+4*16u+40u=384u+62u+64u+40u=550u
mCa=40u
550u-100%
40u-x
550u*x=40u*100%
550x=4000%
x=7,(27)%≈7,3%
Odp: Zawartość procentowa wapnia w palmitynianie wapnia wynosi 7,3%.