Oblicz zawartosc procentową każdego z tlenków we włóknie szklanym o składzie chemicznym 6 SiO2 * CaO * Na2O.
mNa₂O*CaO*6SiO₂=478um 6SiO₂=360u
m CaO=56u
m Na₂O=62u
%SiO₂ = (360/478)*100% = 75,3%
%CaO = (56/478)*100% = 11,7%
%Na₂O = (62/478)*100% = 13,0%
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mNa₂O*CaO*6SiO₂=478u
m 6SiO₂=360u
m CaO=56u
m Na₂O=62u
%SiO₂ = (360/478)*100% = 75,3%
%CaO = (56/478)*100% = 11,7%
%Na₂O = (62/478)*100% = 13,0%