Oblicz zawartość procentową (procent masowy) węgla butanu.
Butan
masa molowa:
procent masowy węgla:
pozdrawiam
(48/58)*100% = 82,7%
mC4H10=48u+10u=58u
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Butan
masa molowa:
procent masowy węgla:
pozdrawiam
(48/58)*100% = 82,7%
mC4H10=48u+10u=58u