Oblicz zawartość procentową (procent masowy) fosforu w kwasie fosworowym
prosze pomóżcie ! to badzo ważne!
H₃PO₄ = 3×1u + 31u + 4×16u = 98u
98 ----- 100%
31------ x
x = 31,6%
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
H₃PO₄ = 3×1u + 31u + 4×16u = 98u
98 ----- 100%
31------ x
x = 31,6%