Oblicz zawartość procentową pierwiastków w mrówczanie wapnia.
Proszę o pomoc to dla mnie bardzo ważne bo jestem zagrożony z chemi i musze to rozwiązać.
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Ca(HCOO)2 - mrówczan wapnia
mCa(HCOO)2 = 40u + 2 * 1u + 2 * 12u + 4 * 16u = 40 + 2 + 24 + 64 = 42 + 88 = 130u
Ca - 40/130
H - 2/130
C - 24/130
O - 64/130
130/130 -100%
1/130 = 0,76%
Ca - 40/130 - 40 * 0,76 = 30,4%
H - 2/130 - 2* 0,76 = 1,52%
C - 24/130 - 24 * 0,76 = 18,24%
O - 64/130 - 64 * 0,76 = 48,64%
wzór mrówczanu wapnia Ca(HCOO)2
mCa = 40u
mH = 1u
mC = 12u
mO = 16u
m Ca(HCOO)2 = 40 + (1+12+16+16)*2 = 40+45*2=130u
%mCa= 40/130 * 100% = 31%
%mH = 2/130 * 100% = 1,5%
%mC= 24/130 *100% = 18,5%
%mO = 64/130 *100% = 49%