oblicz zawartość % dwóch izotopów boru , jezeli masa atomowa boru wynosi 10.81 u , jeden z izotopów ma w jądrze 5 neutronów a drugi 6 . zapisz obliczenia
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¹⁰B
A₁=10
%x₁=?
¹¹B
A₂=11
%x₂=?
mat=10,81 [u]
%x₁->x
%x₂->100-x
mat=A₁*x+A₂*(100-x) / 100%
10,81=10*x+11*(100-x) /100% /*100
1081=10x+1100-11x
1081-1100=-x
-19=-x /*(-1)
x=19
100-19=81
¹⁰B=19%
¹¹B=81%