oblicz zaawartośc procentową wody krystalizacyjnej w 6 wodnym chlorku wapnia..
CaCl2*6H2OmCaCl2*6H2O=40u+2*35,5u+6*18u=40u+71u+108u=219
219u-100%
108u-x%
219x=10800% /:219
x=49%
mCaCl2*6H2O=111u+108u=219u
% H2O = (108/219)*100% = 49,3% H2O
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CaCl2*6H2O
mCaCl2*6H2O=40u+2*35,5u+6*18u=40u+71u+108u=219
219u-100%
108u-x%
219x=10800% /:219
x=49%
mCaCl2*6H2O=111u+108u=219u
% H2O = (108/219)*100% = 49,3% H2O