Oblicz współrzędne punktów przeciecia wykresów funkcji y = ½x² + 6x + 16 oraz y = x + 8
Daje naj :D !!!
{ y=½x²+6x+16 { y = x+8
x+8 = ½x²+6x+16 ½x²+6x-x+16-8 = 0 ½x²+5x+8 = 0 Δ = 25 - 4*½*8 = 25-16 = 9 √Δ=3 x₁ = (-5+3)/1 = -2 x₂ = (-5-3)/1 = -8 y₁ = x₁ + 8 = -2+8 = 6 y₂ = x₂ + 8 = -8+8 = 0
P₁ = (-2,6) i P₂ = (-8,0)
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{ y=½x²+6x+16
{ y = x+8
x+8 = ½x²+6x+16
½x²+6x-x+16-8 = 0
½x²+5x+8 = 0
Δ = 25 - 4*½*8 = 25-16 = 9 √Δ=3
x₁ = (-5+3)/1 = -2
x₂ = (-5-3)/1 = -8
y₁ = x₁ + 8 = -2+8 = 6
y₂ = x₂ + 8 = -8+8 = 0
P₁ = (-2,6) i P₂ = (-8,0)