Oblicz wartość wyrażeń:
x=pierwiatek z 2+3
a)2+5
b)-3x
c)-2x
d)
dla x=√2+3
a)2x²+5=2(√2+3)² +5=2(2+6√2+9)+5=4+12√2+18+5=12√2+27
b)x³-3x=(√2+3)³ -3x =[√8+3·(√2)²·3 +3√2·3² +3³]-(3·(√2+3)=2√2+18+27√2+27 -3√2-9=
26√2+36
c)x²-2x=(√2+3)² -2(√2+3) =2+6√2+9 -2√2-6=4√2+5
d)x²+x² =(√2+3)² +(√2+3)³ =2+6√2+9+2√2+18+27√2+27 =35√2+56
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dla x=√2+3
a)2x²+5=2(√2+3)² +5=2(2+6√2+9)+5=4+12√2+18+5=12√2+27
b)x³-3x=(√2+3)³ -3x =[√8+3·(√2)²·3 +3√2·3² +3³]-(3·(√2+3)=2√2+18+27√2+27 -3√2-9=
26√2+36
c)x²-2x=(√2+3)² -2(√2+3) =2+6√2+9 -2√2-6=4√2+5
d)x²+x² =(√2+3)² +(√2+3)³ =2+6√2+9+2√2+18+27√2+27 =35√2+56