Oblicz wartość sin alfa, cos alfa, ctg alfa jeżeli alfa jest kątrem ostrym i tg= 2
tgα = 2
ctgα = 1/tgα = 1/2
tgα = sinα/cosα
2 = sinα/cosα => 2cosα = sinα
{2cosα = sinα
{cos²α + sin²α = 1
cos²α + 4cos²α = 1
5cos²α = 1
cos²α = 1/5
cosα = √5/5 lub cosα = -√5/5 ale α jest kątem ostrym więc wartość ujemna odpada
sinα = 2 x √5/5 = 2√5/5
Odp.
sinα = 2√5/5
cosα = √5/5
ctgα = 1/2
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Feci, quod potui, faciant meliora potentes
Pozdrawiam :)
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tgα = 2
ctgα = 1/tgα = 1/2
tgα = sinα/cosα
2 = sinα/cosα => 2cosα = sinα
{2cosα = sinα
{cos²α + sin²α = 1
cos²α + 4cos²α = 1
5cos²α = 1
cos²α = 1/5
cosα = √5/5 lub cosα = -√5/5 ale α jest kątem ostrym więc wartość ujemna odpada
sinα = 2 x √5/5 = 2√5/5
Odp.
sinα = 2√5/5
cosα = √5/5
tgα = 2
ctgα = 1/2
----------------------------------------------------------------------------------------------------------
Feci, quod potui, faciant meliora potentes
Pozdrawiam :)