Oblicz wartość sin alfa , cos alfa, ctg alfa, jeżeli alfa jest kątem ostrym i tg= 2.
DAJE NAJ ZA PEŁNA ODPOWIEDŹ
tg alfa = 2
Mamy
tg alfa = y/x , więc y = 2, x = 1
oraz r^2 = x^2 + y^2 = 1^2 + 2^2 =1 + 4 = 5
r = p(5)
sin alfa = y/r
więc
sin alfa = 2/ p(5) = [ 2 p(5) ]/ 5
cos alfa = x/ r = 1/ p(5) = p(5) / 5
ctg alfa = x/ y = 1/2
=============================
p(5) - pierwiastek kwadratowy z 5
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tg alfa = 2
Mamy
tg alfa = y/x , więc y = 2, x = 1
oraz r^2 = x^2 + y^2 = 1^2 + 2^2 =1 + 4 = 5
r = p(5)
sin alfa = y/r
więc
sin alfa = 2/ p(5) = [ 2 p(5) ]/ 5
cos alfa = x/ r = 1/ p(5) = p(5) / 5
ctg alfa = x/ y = 1/2
=============================
p(5) - pierwiastek kwadratowy z 5