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sin α=⅔ i 90°<α<180°.
sin²α +cos²α=1
(⅔)²+cos²α=1
cos²α=1 -4/9
cos²α=5/9
cosα=-√5/3 bo 90°<α<180°
tgα=sinα/cosα
tgα=(2/3)/(-√5/3)
tgα=2/3 *(-3/√5)
tgα=-2/√5 *√5/√5
tgα=-2√5 /5
ctgα=cosα/sinα
ctgα=(-√5/3)/(2/3)
ctgα=(-√5/3)*(3/2)
ctgα=-√5/2